Я використовую Django Rest Framework. і я продовжую отримувати помилку
Exception Type: TemplateDoesNotExist
Exception Value: rest_framework/api.html
Я не знаю, як я йду не так. Це перший раз, коли я пробую руки на REST Framework. Це код.
views.py
import socket, json
from modules.data.models import *
from modules.utils import *
from rest_framework import status
from rest_framework.decorators import api_view
from rest_framework.response import Response
from modules.actions.serializers import ActionSerializer
@api_view(['POST'])
@check_field_exists_wrapper("installation")
def api_actions(request, format = None):
action_type = request.POST['action_type']
if action_type == "Shutdown" :
send_message = '1'
print "Shutting Down the system..."
elif action_type == "Enable" :
send_message = '1'
print "Enabling the system..."
elif action_type == "Disable" :
send_message = '1'
print "Disabling the system..."
elif action_type == "Restart" :
send_message = '1'
print "Restarting the system..."
if action_type in ["Shutdown", "Enable", "Disable"] : PORT = 6000
else : PORT = 6100
controllers_list = Controller.objects.filter(installation_id = kwargs['installation_id'])
for controller_obj in controllers_list:
ip = controller_obj.ip
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((ip, PORT))
s.send(send_message)
s.close()
except Exception as e:
print("Exception when sending " + action_type +" command: "+str(e))
return Response(status = status.HTTP_200_OK)
models.py
class Controller(models.Model):
id = models.IntegerField(primary_key = True)
name = models.CharField(max_length = 255, unique = True)
ip = models.CharField(max_length = 255, unique = True)
installation_id = models.ForeignKey('Installation')
serializers.py
з django.forms імпортувати віджети з rest_framework імпортувати серіалізатори з module.data.models import *
class ActionSerializer(serializers.ModelSerializer):
class Meta:
model = Controller
fields = ('id', 'name', 'ip', 'installation_id')
urls.py
from django.conf.urls import patterns, url
from rest_framework.urlpatterns import format_suffix_patterns
urlpatterns = patterns('modules.actions.views',
url(r'^$','api_actions',name='api_actions'),
)
How do I get the form?